60x^2+90x-15=0

Solution for 60x^2+90x-15=0 equation:

60x^2+90x-15=0

a = 60; b = 90; c = -15;
Δ = b2-4ac
Δ = 902-4·60·(-15)
Δ = 11700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11700}=\sqrt{900*13}=\sqrt{900}*\sqrt{13}=30\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-30\sqrt{13}}{2*60}=\frac{-90-30\sqrt{13}}{120}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+30\sqrt{13}}{2*60}=\frac{-90+30\sqrt{13}}{120}
$